TEKS Support |
This unit contains activities that support the following knowledge and skills elements of the TEKS.
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(3) (B) |
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(3) (C) |
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The mathematical prerequisites for this unit are
The mathematical topics included or taught in this unit are
The equipment list for this unit is
Teacher Notes |
"Simple Model" Context Overview |
This unit is multicontextual. However, several major contexts are revisited more than once during the unit. Those include the portion of the moons visible surface that is illuminated versus time, the length of daylight versus time, and a Ferris wheel riders height versus time. Data for the first two contexts appear in the first activity as part of an introduction to periodic behavior. However, it is not until the last activity that students are able to create sinusoidal models describing each of these relationships. After creating these models, students use them to make predictions for fishermen about the amount of moonlight and for SAD sufferers about the length of daylight.
Mathematical Development |
The unit begins with an introduction to periodic phenomena. Students generate descriptions of the characteristics of periodic data and learn vocabulary connected with periodic graphs (period, amplitude, axis of oscillation). Then they draw graphs describing a Ferris wheel riders height over time and learn how changing the Ferris wheels speed, diameter, or height above the ground affects the period, amplitude and axis of oscillation of their graphs. In order to gather more precise information on the shape of these height-versus-time graphs, students use bicycle wheels as scaled-down models for Ferris wheels. They roll their wheels and record the height of a dot on the tire and the distance the wheel has rolled.
Collection of the wheel data prepares students for a discussion of the unit circle, radian measure, and the sine function. This is followed by a student investigation of sinusoidal functions expressed in the form y = A sin(Bx + C) + D. Through their investigations students discover which graphical features are controlled by each of the constants A, B, C, and D. Then students apply what they have learned from their investigations and fit (by hand) sinusoidal functions to data. If fitting sinusoidal functions is a regression option on the calculators that you are using, students use that option to fit sinusoidal functions to data.
Unit ProjectSwing Dance |
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Materials Needed |
Motion detector apparatus (for example, CBL, motion detector, calculator) Pendulum.83p String Plastic soda bottle or water jug Stopwatch |
Students use motion detectors to collect data on a swinging pendulum. Then they fit sinusoidal models to their data. They also investigate what they can do to the pendulum in order to change the phase shift, amplitude, and period of its recorded motion.
If you have access to a computer on which students can store their data, you could spread this project out over the course of the unit. Students could begin collecting data on pendulum swings early in the unit and then determine models based on their data toward the end of the unit.
Teaching SuggestionsPreparation Reading |
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This reading introduces students to three contexts that will be used in this unit: patterns in temperature over time, patterns in the length of daylight over time, and patterns in the amount of illuminated moon surface over time.
Activity 1Everyday Patterns |
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This activity introduces students to periodic patterns from a variety of contexts. In addition, it introduces the terms periodic, period, and amplitude.
Students should work in small groups on this activity. Because many of the contexts introduced in Activity 1 will be revisited later, advise students to save their work so that they can refer to it later.
Set aside some time for students to share their answers to Items 1 (b, f, and g). In particular, use Item 1 (g) to motivate the need for an equation to model the relationship between the illuminated portion of the moons surface and time. In the last activity, students will create such a model. So, set up the need for it here.
The U.S. Navy has two Internet sites that provide interesting resources that are relevant to Items 1 and 3:
Times of sunrise/sunset, moonrise/moonset, twilight, and other astronomical data are available from the United States Navy Observatorys (USNOs) Astronomical Applications Department at http://aa.usno.navy.mil/data/
The site http://tycho.usno.navy.mil/srss.html provides virtual reality moon- phase pictures. You have only to specify the century, year, month, day, hour, and time zone.
For example, Item 3 presents data on the length of daylight in Boston, Massachusetts. You can extend this Item using data relevant to your area. Use USNOs site to get data for the city nearest you.
The data in Item 4 are not as perfectly periodic as the daylight data. Help students to understand that periodic behavior in the real world includes some "noise."
Homework 1Follow the Bouncing Ball |
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In this assignment students sort out which types of situations involve periodic patterns and which do not. The first six items all involve balls (baseballs, basketballs, tennis balls, etc.) The last item gives students an opportunity to add their own examples of periodic behavior to those already introduced.
Note that in this assignment students are asked to classify motion as periodic according to a mathmeticians definition: f(t) = f(t + np) where n is an integer and p is the period. (students need not see this formal definition.) Under this definition, amplitude and period are constant. Engineers, on the other hand, accept a more relaxed definition of periodic. Basically any motion that is repeated in equal intervals of time would be considered periodic. This definition allows for changes in amplitude.
Give students an opportunity to share their answers to Item 8 before beginning Activity 2.
Activity 2What Goes Around Comes Around |
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In this activity, students begin creating graphs to model a Ferris wheel riders height over time. In addition, they make the connection between circular motion measured in revolutions per minute (rpm) and velocity.
Before students begin this activity, review the relationship between a circles circumference, C, and its radius, r: C = 2p r. After the review, assign students to small groups to work on the activity.
Item 4 involves the motion of a Ferris wheel ride. The development of the sine function will rely heavily on this physical model. For this item, students make a graph of the relationship between the riders height and time. If a group has trouble coming up with the graph, suggest that they create a data table similar to the one shown in Example 1.
Time (sec) |
Height above ground (m) |
0 |
3 |
10 |
3 + 26 = 29 |
20 |
55 |
30 |
29 |
Example 1. Height-versus-time data.
Help students notice, without telling them, that 10-second intervals correspond to a quarter-turn on this Ferris wheel. Because of the periodic nature of these data, the heights corresponding to times 40, 50, 60, and 70 are a repeat of the height values in Example 1.
Conclude the activity with a discussion of Item 7. To facilitate this discussion, you may want to ask groups to re-draw one or more of their graphs from Item 6 on large sheets of paper and hang these graphs in the front of the room.
Homework 2Going Nowhere Fast |
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This assignment gives students an opportunity to practice material learned in Activity 2.
One method of getting a graph for Item 4(a) is to have students make a data table. (See Example 2.) A picture can help them determine the values for the distance from the entrance. Assume when time = 0, the rider is closest to the entrance. Because the carousel rotates 5 times each minute, it makes one complete revolution in 1/5 min or every 12 seconds. So, selecting times in 3-second increments correspond to quarter turns around the carousel.
Time (sec) |
Distance (ft) |
0 |
7 |
3 |
36.4 |
6 |
51 |
9 |
36.4 |
Example 2. Distance-versus-time data.

Example 3. Position of rider after 3 seconds
Students can use the Pythagorean Theorem or the distance formula to find the distance between the rider and entrance at time = 3 sec. Using the Pythagorean Theorem and solving d2 = 222 + 292 for d, gives a distance of approximately 36.4 ft when time = 3 sec.
Activity 3Spinning Your Wheels |
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Materials Needed |
Bicycle wheel or bicycle Variety of circular objects to roll (garbage can lids, hoola hoops, etc.) Handout 1 Tape measures (1 per group) Meter sticks (1 per group) Masking Tape |
The goal of this activity is to determine, through experimentation, the graph of height versus time as a person rides a Ferris wheel. Instead of a Ferris wheel, students roll a bicycle wheel (or some other round object) and collect height-versus-distance data from the wheel.
Begin this activity with the following question. This question gives students an opportunity to suggest details of how the experiment could be conducted before they are told the details. Heres the question:
How could a bicycle wheel be used to collect data relevant to a Ferris wheel riders height above the ground during the ride? Describe how you might conduct such an experiment.
Students should work in groups of three or four. Youll need one wheel or circular object per group. One student can roll the wheel, another one (or two) can measure the distance and height, and the last can record the data on Handout 1. Although this activity suggests that data be collected from rolling a bicycle wheel (or bicycle), you may substitute some other circular object such as a large garbage can lid or a hoola hoop. In fact, for the purposes of class discussion, plan to assign different groups circular objects of various sizes. Be sure to instruct students to keep the object that they roll perpendicular to the floor.
In Item 2 students should use the meter stick to measure the height of the dot and the tape measure on the floor to measure the distance the wheel has traveled. Check that students are collecting at least six measurements per revolution of their wheel over at least three revolutions. Also, make sure that they dont take so many measurements that they cant complete this activity in a reasonable amount of time. Finally, remind students to save their data for use in Activity 4.
In Item 3 students should capture the flow of their data with a smooth curve. Remind them that they want to catch the essence of the relationship between height and distance with their graph and not simply play "connect the dots."
At the end of the activity, have groups share what they have discovered about their data. In particular, if groups used wheels of different radii, have students find the connection between the radius of their wheel and the period and amplitude of their graph. They should be able to reason that the period of their graph is 2p r and the amplitude is r, where r is the radius of their wheel.
Homework 3Going Around In Circles |
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Materials Needed |
Transparency 1 |
This assignment introduces the concept of radians as a measure of directed arc length on a unit circle. It concludes by developing the sine function.
Students can work individually on this assignment or in pairs. You might want to assign it for homework and then allow additional class time to complete the assignment after students have had a chance to ask questions.
In Item 1 students use direct circumference calculations to generate periodic data for a hypothetical tire. The graph they produce is a translated version of y = sin(x). Make sure that they connect the period of their graph with the circumference of their wheel2p ft. Encourage them to write exact answers as well as decimal approximations to Items 1(ac) and 1(e).
Item 2 Introduces students to radian measure. You should spend some time discussing this concept. Radian measure is a method of describing the size of an angle without resorting to an arbitrary unit. Degrees, grads, and mills are arbitrary units that were adopted for specific purposes. In contrast to this the size of an angle, expressed in radian measure, has no unit. The following figure shows how the size of an angle is determined.

The size of the angle, Ð ABC, is determined as follows:
Draw a segment of a circle, of any radius, with the center at the vertex of the angle and the segment crossing both rays that define the angle.
Measure the radius, R, and the length of the arc between the rays, S, using the same unit of linear measure for both.
The size of the angle in radian measure is the ratio of S to R.

Notice that this ratio will always be unitless, because S and R are measured in the same units of length.
Example: If R = 20 inches and S = 35inches, then Ð ABC = 1.75
It is correct to say that Ð ABC=100o = 111 grad = 1.75. The first two expressions of the size of the angle are in terms of defined, but arbitrary, units. The last expression of the size has no units, so we know it is in radian measure.
The definition of the size of an angle in radian measure can be used to produce a relationship between the radius and the arc length of a segment of a circle that is subtended by the angle.
Arc length = (Anglein radian measure)(Radius)
In Item 3 students collect vertical-displacement-versus-angle data from a graph of a unit circle. A scatter plot of their data should resemble a portion of the graph that they drew in Item 1(d). Both graphs have the same period and amplitude. They will need to use their graphing calculators to overlay a graph of y = sin(x) on the data from part (a). Make sure that students check that their calculators are in Radian mode. To choose window settings that match the ones for their graphs in part (b), they will have to convert radian measure involving p to their decimal equivalents.
Items 5 and 6 work students work with the definition of radian measure of a central angle: q = s/r, where s is the length of arc swept out by the angle and r is the radius of the circle. Emphasize the linear units associated with s and r, and the fact that the size of the angle has no units. Do not use the word "radian" as a unit. After this assignment check to see that they understand this relationship.
Conclude this assignment by letting students share their answers to Item 5.
Activity 4Learning A, B, C, and D |
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Materials Needed |
Supplemental Activity1 |
This activity develops sinusoidal functions, y = A sin(Bx + C) + D, and prepares students to apply what they have learned so that they can fit sinusoidal functions to periodic data.
If possible, students should work in the same groups as they did in Activity 3.
The investigation to determine what the control numbers A, B, C, and D actually control may take students longer to complete than you expect. You have three options for Item 1 in this Activity. Options 1 and 2 are more open and require students to plan a careful investigation on their own. Option 3 is more directive.
Option 1: Students use their calculators for the investigation written in Activity 4. Warn students to be careful placing parentheses. For example, if students enter y = 5 sin(2(x 3) + 7 into a TI-83, they will not get the same graph as that produced by y = 5 sin(2x 3) + 7. All thats different between the two equations is a single parenthesis.
Option 2: If you feel that the investigation as presented in Item 1 is too open to be meaningful to your students, replace Item 1 with Supplemental Activity 1, "Directed Investigation."
After students have completed their investigation, check that they have discovered the relationship between the control number B and the period: that is, period = 2p/|B|. Its best if students discover this relationship without being told directly.
If students get stuck on Item 4, tell them to pay attention to the order of the transformations when the equation is in y = A sin(Bx + C) + D form. First, A and B control the vertical and horizontal stretch (or compression) of the graph, respectively; second, C and D slide the graph horizontally or vertically, respectively. In other words, the stretches (controlled by A and B) act before the slides (controlled by C and D). Take, for example, Item 4(a). To graph y = 3sin(x) + 2, begin with the graph of y = sin(x). First, stretch the amplitude by a factor of 3 and then slide the graph up 2 units, in that order.
Students will need their wheel data from Activity 3 for Item 5. Encourage them to create their model from the wheel context before graphing the data. Then they can make additional adjustments after they overlay the graph of their model on a scatter plot of their wheel data. You may want to discuss this item in class or have one or more groups present their solutions to the class.
Homework 4Sine Up! |
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This assignment provides practice matching sinusoidal functions with graphs.
Make sure that students understand the role of each of the constants in the model
If you find students calculator-produced graphs dont match how you expect the graph to appear, check that they have entered the equations into their calculators using the correct number and placement of parentheses. Also check that they are in Radian mode and have chosen appropriate window settings.
Item 1 asks students to draw by hand the graphs of two equations and compare each to the graph of y = sin(x). These equations have different periods but the same amplitude. It is helpful if students use scaling that involves p so that the exact periods of each of the graphs can be ascertained from students hand-drawn graphs.
Items 2 introduces the term phase shift. Be sure to use this term in subsequent discussions. You may want to ask students to define, in their own words, what the phase shift of a sinusoidal function is.
Check that students were able to complete Item 6 before you move on to Activity 5. You may want to let one or more students present their methods for determining their models.
Activity 5Moonlight and Sunlight |
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Materials Needed |
Handout 2 |
In this activity, students determine models describing the moon data and length of daylight data first introduced in Activity 1. This gives them a chance to fit sinusoidal models to real data and then use their models to answer questions relevant to the given situation.
Initially, students should fit their models by hand. Later, provided your graphing calculators have sinusoidal regression as one of their regression options, students can use regression to fit sinusoidal functions to their data. Warning: If students want to check the adequacy of a model using a residual plot, they should compute the residuals manually rather than using the residuals automatically computed by the calculator. (Some calculators automatically-computed residuals for nonlinear regressions are incorrectly computed.)
In Item 1 students fit a sinusoidal model to the moon data. Have students note the order suggested by this item for fitting the sinusoidal equation. The period and amplitude are adjusted first (the stretches). Then students are left to their own devises to make the appropriate slides. The vertical shift, changing the axis of oscillation is fairly easy. However, students may need some help determining the phase shift. They can begin by noting that the first "peak" in the graph of their unshifted model occurs at t = period/4. From their moon data, they can approximate the t-value that corresponds to the first "peak" in these data. Then they should use these two pieces of information to determine the value of C.
Students will need Handout 2, a 1997 calendar, in order to complete Item 2.
In Item 3 students fit a sinusoidal function by hand to the length of daylight data introduced in Activity 1. Check that students by-pass the data and determine the value of B directly from their knowledge that there are 365 days in a year. In Item 3(b) they use their calculators to fit a sinusoidal model to these data. Omit this item if your graphing calculators do not have this feature. (An alternative would be to enter these data in a spreadsheet such as Excel and then use the spreadsheets regression capabilities to fit the sinusoidal model.)
Homework 5Modeling Ferris Wheel Rides |
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In this assignment, students create sinusoidal models to describe a Ferris wheel riders height above the ground over time.
Check that students are able to determine an equation modeling the riders height above the ground during the Ferris wheel ride. If students are unable to complete this assignment, review strategies for determining the constants A, B, C, and D in the sinusoidal model from the context.
Supplemental Activity 1Directed Investigation |
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This activity is a more directed version of Item 1, Activity 4. Students investigate how the constants in sinusoidal models of the form y = A sin(Bx + C) + D affect the graph.
Handout 1Wheel Data |
Units of Measurement: ___________
Distance wheel moves |
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Height of dot above the floor |
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Distance wheel moves |
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Height of dot above the floor |
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Distance wheel moves |
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Height of dot above the floor |
Figure 1. Height versus distance for turning wheel.
Handout 2 |
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Supplemental Activity 1Directed Investigation |

The period is 2p » 6.28 and the amplitude is 1.
The value of A does not change the period of the graph; however, it does change the amplitude. The amplitude of y = A sin (x) is A. The effect of multiplying by A where A > 1 is to stretch the wave vertically. The effect of multiplying by A where 0 < A < 1 is to compress the wave vertically. If the sign of A is negative, then the wave reflects over the x-axis. Upward loops of the wave turn into downward loops and vice versa.

The value of B affects the period of the wave. The amplitude is not changed. If B > 1, the period gets smaller; if B < 1, the period gets longer. Instead of 2p the period becomes 2p /B. Below are some sample graphs.

When you change the value of C, neither the period or amplitude are changed. If C is positive, the graph moves C units to the right; otherwise the graph shifts left.

Adding D to the sine function shifts the graph up D units if D is positive and down if D is negative.

Transparency 1Radian Measure |

Figure 1. Arcs measuring 3 and 3p/4 on circles with different radii.
Annotated Student Materials |
Preparation ReadingPlanning Cycles |
How do power companies predict the amount of energy consumers will be using in the winter? In the summer? How does a department store plan to buy the right quantities of sweaters and bathing suits? The answers to these and many other planning questions rely on predicting how temperatures will vary over time. In places where seasonal temperatures change dramatically, companies plan their budgets and predict consumer buying patterns accordingly. Predicting the seasonal pattern of hours of daylight is important for another very different reason. Seasonal Affective Disorder (SAD) affects approximately 10 million Americans. Many SAD sufferers get depressed in the winter when the hours of daylight are shorter. Understanding the cyclical nature of hours of daylight helps physicians treating SAD sufferers plan for helpful treatments.Even the phases of the moon affect our plans. As the moon moves about the earth, its appearance changes on a regular cycle. It changes from new moon when the moon is totally dark to full moon when the moon is totally illuminated (lit by the reflection of the sun). Since the phases of the moon affect the tides, people who fish need this information to plan. (A number of websites for people who fish have links to sites with information on the moons phases. The U.S. Naval Observatory hosts one of those sites.) The military also plans night operations based on the amount of light the moon casts.In this unit, you will use mathematics to model the behavior of quantities that change based on cycles such as those described above.
Activity 1Everyday Patterns |
= 1, 2, 3




January 5, January 10, January 15 and January 20
Figure 1. Illumination of the moon on four nights in January
Sample answer #1: The moon goes through phases: new moon (surface dark), crescent moon, first quarter (half of moons surface illuminated), full moon, third quarter (half of moons surface illuminated), crescent, new moon. Then the pattern repeats.
Sample answer #2: The moon goes from fully illuminated to totally darkened then back to fully illuminated. This cycle repeats over and over.
Student answers will vary depending on their estimates for the length of the moons cycle. At this point in the unit, the logic of student arguments is more important than correct answers.
Sample answer #1: The moon completes its cycle approximately once a month. On February 14th, the moon should look similar to the way that it looked on January 15th. So, roughly half of the moon should be illuminated.
Sample answer #2: From the pictures in Figure 1, it appears that the moon went from no illumination on January 10th to almost total illumination on January 20th. So it took a few more than 10 days, say 13 days, for the moon to complete a half-cycle; in other words, to go from total darkness to full illumination. From January 20 to February 14 is 25 days, just short of a complete cycle. So the Moon on February 14 should be almost (but not quite) a full moon.
April 1997 |
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Figure 2. April Calendar, 1997.
Sample answer: Assuming that the moons cycle is roughly one month, Jason and his father should have chosen a date somewhere around April 20, which is a Sunday.
One group member, however, felt strongly that a complete cycle of the moon takes less than one month. So, she wanted to select Sunday April 13th.
How sure are you of your answers to parts (b) and (c)? Perhaps the additional data given in the next item will help.
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1/5 |
1/10 |
1/15 |
1/20 |
1/25 |
1/30 |
2/4 |
Day of year |
5 |
10 |
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25 |
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35 |
Portion illuminated |
0.20 |
0.02 |
0.43 |
0.89 |
0.98 |
0.66 |
0.17 |
Date |
2/9 |
2/14 |
2/19 |
2/24 |
3/1 |
3/6 |
3/11 |
Day of year |
40 |
45 |
50 |
55 |
60 |
65 |
70 |
Portion illuminated |
0.04 |
0.48 |
0.91 |
0.97 |
0.63 |
0.12 |
0.07 |
Date |
3/16 |
3/21 |
3/26 |
3/31 |
Day of year |
75 |
80 |
85 |
90 |
Portion illuminated |
0.52 |
0.92 |
0.96 |
0.57 |
Figure 3. Illuminated portion of the moon.
Make a scatter plot of the data in Figure 3. For your plot, put "portion-illuminated" on the vertical axis and "day of the year" on the horizontal axis. Then draw a smooth curve (no sharp corners) through the points on your scatter plot.
Answer:

The portion of the moons visible surface that is illuminated increases from 0 (new moon) to 1.0 (full moon) and then decreases back to 0 (new moon). Based on these data, this pattern of increase, followed by decrease, (beginning about January 10th) repeats itself twice and starts to repeat a third time from 1/5/97 3/3/97.
Sample answer: The moon is full around day 114, April 24th, which is a Thursday. So, Jason and his father should have taken their fishing trip on Friday, April 25th..

The predicted date based on the graph is somewhat later than the one in part (c). Looking at the dates close to when the moon is full, 1/25, 2/24, and 3/26, it appears that the moon repeats its cycle about every 30 days. Based on Figure 3, on January 20 the moon is not fully illuminated (as we assumed in part (c)); instead, it is fully illuminated approximately 5 days later. This accounts for the earlier prediction in part (c). The answer based on the graph is more accurate because it is based on more data and on data that is more precise than the answer in part (c) which is based on only 4 pictures of the moon.
Sample answer: The graph is not useful because it has not been extended far enough to include September. You would have to get a really long paper to extend the graph that far. If you were drawing it by hand, you would probably lose some accuracy as you extend the graph.
On the other hand, if you could find an equation, then you could enter it into your calculator, draw the portion of graph that corresponds to day numbers September, and get your answer from the graph.

Students should draw a smooth curve through the points on the scatter plot in (b).
Date |
12/31 |
1/30 |
3/1 |
3/31 |
4/30 |
5/30 |
6/29 |
7/29 |
Day Number |
0 |
30 |
60 |
90 |
120 |
150 |
180 |
210 |
Length (hours) |
9.1 |
9.9 |
11.2 |
12.7 |
14.0 |
15.0 |
15.3 |
14.6 |
Date |
8/28 |
9/27 |
10/27 |
11/26 |
12/26 |
1/25 |
2/24 |
3/26 |
Day Number |
240 |
270 |
300 |
330 |
360 |
390 |
420 |
450 |
Length (hours) |
13.3 |
11.9 |
10.6 |
9.5 |
9.1 |
9.7 |
11.0 |
12.4 |

Figure 5. Axes for "length of day" versus "day number."
Sample answer:

Sample answer (student answers should be close to these): days 80 and 270.
Sample answer (student answers should be close to these): days 445 and 635.
The two answers in part (d) should differ from the corresponding answers in part (c) by 365 days, 1 year.
The graph would rise and then fall a total of four times. The highest point on the graph is approximately 15 hours and the lowest is around 9 hours.

Figure 6. Average monthly temperatures (°F) for Boston.
Months 7, 19, and 31 appear to be the hottest. These month numbers correspond to July 1995, July 1997, and July 1998, respectively. The average temperature appears to be about 74° F.
Sample answer: For these data February 1995 was colder than January 1995. However, January 1996 and January 1997 are the coldest months in each of these years. So, January tends to have the lowest average temperature. The average temperature for January appears to be about 29° F.
The graph has an up-and-then-down pattern that repeats every 12 months. The average temperatures are low in January, get progressively warmer until July, and then drop until around January. This pattern repeats itself every year.
Sample answer: All of the graphs share an up-and-then down pattern. The time it took to complete one up-down cycle differed from graph to graph. The height difference between the lowest point on the graph and the highest point on the graph also differed from graph to graph.

Figure 7. Graphs of three periodic functions.
A: period is » 2; B: period is » 6.3; C: period is » 3.
A: amplitude is 0.5(5 3) = 1; B: amplitude is 0.5(2 + .4) = 1.2; C: amplitude is 0.5(3 + 4) = 0.5.
Item 1: A little less than 30 days.
Item 2: One second.
Item 3: 365 days.
Item 4: Every 12 months.
Item 1: The amplitude is 0.5. Since the new moon has 0% of its surface illuminated and the full moon has 100% of its surface illuminated, the graph will oscillate between 0 and 1. So, the amplitude will be exactly 0.5. Very sure of my answer.
Item 2: 0.5(20 5) = 7.5 feet. Very sure of my answer.
Item 3: 0.5(15.3 9.1) = 3.1 hours. Not as sure of my answer because it is not known if 9.1 hours is the shortest day and 15.3 is the longest day.
Item 4: 0.5(74° 29°) = 22.5°. Not as sure of my answer because the highest and lowest point were estimated from the graph. Also, because the pattern does not repeat itself perfectly.
Sample answer: The patterns in Items 1 and 3 will continue indefinitely or at least for a very long time. Changes in the Earths rotational speed may change these patterns very gradually over time. But that change wont be noticeable in our lifetimes.
The pattern in Item 2 will continue until you tire of riding your bicycle and stop riding. Then the pattern will stop.
Because of global warming, the pattern in Item 4 will change. The pattern will drift upward causing hotter summers and warmer winters.
Sample answer:

Yes, this graph is periodic. The same pattern repeats over and over as the horse goes rhythmically up and down during the ride. Based on the graph, the period is 10 seconds. (In other words, it takes the horse approximately 5 seconds to move from its lowest point to its highest point and then another 5 seconds to return to its lowest point.)
Homework 1Follow the Bouncing Ball |
Sometimes the motion of a ball produces a periodic pattern. Its motion repeats itself in equal intervals of time. Other times, the motion of the ball produces an oscillating pattern that varies between alternate extremes. Its back-and-forth or up-and-down oscillating pattern has some, but not necessarily all, of the characteristics of a periodic pattern. For example, perhaps the amplitude of the basic repeating shape diminishes over time. In Items 16, you are asked to decide whether or not a balls motion is approximately periodic.
No, the ball goes up and then comes down. This pattern does not repeat so the graph is not periodic.
No, the ball goes up and then comes down once. It does not alternate between extremes of up and then down.
Although the ball repeats its up and down motion as it bounces, the heights of the bounces decrease over time. This means that the time between bounces also decreases. Because the up and down pattern changes as the ball bounces, the graph of height versus time is not periodic.
Sample answer: The ball repeats its up and down motion as it bounces. The period is the time between two consecutive bounces on the floor. Perhaps you could ask other students to use stop watches to time how long each bounce takes. The amplitude is half of the height of each bounce. Because of the way the ball is being bounced, this height stays the same for each bounce.
Sample answer: No, the graph would not be periodic. Although the height would go up and down, the time between highs and lows would not be the same. For lobs, heights would be higher than for long drives. So, provided the players mix their shots, the graph would not be periodic.
Sample answer: The players do not mix their plays. Both players must hit each shot exactly the way they hit their previous shot. They would have to hit the ball at the same angle, on the same spot on their racket, with the same force each time. It would be impossible (or nearly impossible) for two players to duplicate their shots exactly play after play.
Sample answer: In order for the graph to be periodic, the champion would need to hit the ball at the same angle and with the same force each time. Using the graph, you could determine the period by measuring the time between two consecutive hits of the ball. The amplitude would be half of the farthest distance that the ball travels from the paddle.

Figure 8: Rope swing.
Sample answer: The graph will not be periodic. If the swing is not pushed repeatedly, each of your brothers swings (away from you and then toward you) will be smaller. From swing to swing, his farthest distance from you will decrease and his closest distance to you will increase. So, the amplitude, 0.5(maximum distance-minimum distance), will change from swing to swing. However, his distance from you on each swing will oscillate back and forth from a (variable) closest point to a (variable) farthest point.
If you push the swing with the same force each time, then the distance- versus-time graph should be approximately periodic. The period is the time between pushes and the amplitude is half the difference between his farthest distance from you and his closest distance from you.
Items 7 and 8 deal with contexts that do not necessarily involve playing ball.
Month |
Mar 83 |
Apr |
May |
June |
July |
Aug |
Starts |
124.3 |
122.1 |
161.5 |
160.1 |
148 |
159.8 |
Month |
Sept |
Oct |
Nov |
Dec |
Jan 84 |
Feb |
Starts |
139.6 |
147.8 |
122.1 |
103.2 |
102.7 |
120.2 |
Figure 9. Housing starts 3/832/84.

Base your answers to the items that follow on the graph that you have drawn for part (a).
December and January have the fewest. In many areas in the U.S., you could not begin building in December or January because the ground is frozen. So, you would expect fewer housing starts during winter months.
May, June, and August have the highest number of housing starts. The largest number of housing starts occurred in late spring (May) and continued into the summer months of June and August. Particularly in parts of the country that have cold winters, it is important to begin houses in the spring and summer so that the house (or at least the outside of the house) will be completed before winter. Buyers with school-age children may want to start houses in the spring so that they can move into their houses before the next school year.
Sample answer: Most likely because the July 4th holiday cuts out several possible work days in which to start new homes. This is a trend that should be expected every year, since July 4th is a yearly holiday.
Sample answer: If housing starts are seasonal, then it seems reasonable to expect the same patterns to occur year after year. Youd expect more housing starts in the spring and summer and fewer in the fall and winter. This trend may be due, in part, to weather conditions.
However, it also seems reasonable that housing starts are tied to the economy. When the economy is good, you would expect an increase in the number of housing starts for all months. When the economy is depressed, then housing starts will probably decline for all months. So, it seems reasonable that the seasonal up-and-down pattern in housing starts would change and would not be purely periodic.
In order to check the whether housing starts are approximately periodic, you would need more data.
Sample answer: Consider the motion of a yo-yo moving up and down along a string. If you plot the height from the ground of the center of the yo-yo over time, you will get a repeating up and down pattern. The period would be the time between consecutive downward throws of the yo-yo and the amplitude would be approximately half the length of the yo-yo string.
Activity 2What Goes Around Comes Around |
= 4, 5, 6, 7
Nauta-Bussink, a company based in Holland, sells amusement park rides. Among its most popular rides are the giant 33-meter, 44-meter, and 55-meter Ferris wheels. (These sizes refer to the height of the top of the wheel.)

Figure 10. Schematic drawing of a 33-meter Ferris wheel.
The wheels turn slowly at the start of the rides, then rotate at a fairly constant speed until they slow for the stop. Details about each of these rides appear in Table 1.
Wheel height (meters from ground to top of wheel) |
Wheel diameter (meters) |
Revolutions per minute |
33.00 |
29.5 |
2.6 |
44.00 |
40.7 |
1.5 |
55.00 |
52.00 |
1.5 |
Table 1. Technical details for three popular Ferris wheels.
Imagine that one amusement park has all three Ferris wheels and that your friend rides each one.
If the wheel makes 2.6 turns in one minute, it takes 1/2.6 » 0.3846 min to make one complete turn. Convert this time to seconds to get approximately 23 seconds.
Note: The diameter of the 33-meter Ferris wheel is 29.5 meters (See Table 1.)
Each time the wheel makes a complete revolution, the friend travels (29.5m.)(p ) » 92.7 m.
The friend travels at approximately 92.7 m./23 sec » 4.0 meters per second.
It will take about 127.5 seconds for the friend to travel 510 meters. During this time he will turn approximately 5.5 times around the wheel. Hell be at the top of the wheel or 33 meters above the ground.
Riders on the 44-meter Ferris wheel would travel at approximately 3.2 meters per second, about 0.8 meters per second slower than the riders on the 33-meter Ferris wheel.
The riders on the 55-meter Ferris wheel travel faster than those on the 44-meter Ferris wheel. The two wheels make the same number of revolutions per minute. However, the riders on the 55-meter Ferris wheel travel a greater distance each time they circle the wheel. Therefore, they must be going faster.
It takes 1/1.5 or 2/3 min or 40 seconds.
Answer:

equation of graph: y = 26sin((2p/40)(x 10)) + 29
20 sec
20, 60, and 100 sec. Two consecutive times differ by 40 sec, one period.
Draw a horizontal line that divides your graph into these two parts. This line is called the axis of oscillation. What equation describes the axis of oscillation for the 55-meter Ferris wheel?
Height = 29 m. or y = 29
33-meter Ferris wheel:
This wheel makes 2.6 revolutions in one minute. So the period is (1/2.6)(60) » 23 sec. The amplitude is 14.75 m. (half of the diameter). The axis of oscillation is height = (0.5)(29.5) + (33.0 29.5) = 18.25 m. (or y = 18.25). (This is same as the wheels height above the ground plus the wheels radius.)
44-meter Ferris wheel:
This wheel makes 1.5 revolutions per minute. Thus, it takes 2/3 min. or 40 sec. to complete a single revolution. So, the period is 40 sec. and the amplitude is 20.35 m. (half of the diameter). The axis of oscillation is height = 0.5(40.7) + (44.0 40.7) = 23.65 m. (or y = 23.65).
Sample answer: Student graphs should be similar to the one below.

equation of graphs: y = 26sin((p/20)x p/2) + 29
y = 26sin((p/40)x p/2) + 29
Sample answer:

equation of graphs: y = 26sin((p/20)x p/2) + 29
y = 26sin((p/10)x p/2) + 29
Sample answer:

equation of graphs: y = 26sin((p/20)x p/2) + 29
y = 26sin((p/20)x p/2) + 36
Sample answer:

equation of graphs: y = 26sin((p/20)x p/2) + 29
y = 26sin((p/20)x p/2) + 27
The speed at which the wheel turns.
The diameter of the wheel.
The height of the wheels axle.
Homework 2Going Nowhere Fast |
The only carousel owned by the U.S. government is located in Glen Echo Park, Washington D.C. The carousel is 48 feet in diameter. It turns counter-clockwise at a top speed of five revolutions per minute. Suppose that you have chosen to ride a horse that is in the outer row. Your horse is about two feet from the edge.
The radius of the circle made as you ride on an outside horse is 22 feet. The circumference of a circle with radius 22 feet is 44p ft » 138.2 ft.
About 691 ft/min or approximately 7.9 miles per hour.
The friend is traveling around a circle with circumference 36p ft » 113.1 ft. She is traveling 565.5 ft/min or approximately 6.4 miles per hour. So, you are riding 1.5 miles per hour faster than your friend.
Sample answer:

equation of graphs: y = 22sin((p/6)x p/2) + 29
Assumptions: the carousel is moving at its top speed; my horse is 5 ft from the entrance when time = 0.
Sample answer:

equation of graphs: y = 18sin((p/6)x p/2) + 29
The periods are the same, 12 seconds. However, the amplitudes differ. The amplitudes for the graphs in parts (a) and (d) are 22 m. and 18 m., respectively.
Activity 3Spinning Your Wheels |
= 8, 9, 10
For Item 4, Activity 2 you were asked to graph the height of a rider at various times during a Ferris wheel ride. In order to make a precise plot of the riders height versus time, you need more data. However, you cant fit a full-sized Ferris wheel into your classroom. Youll need something smaller to model the motion of a Ferris-wheel rider. Instead of an actual Ferris wheel, youll collect data from a bicycle wheel (or some other round object).

Figure 11. Measuring the distance the wheel rolls and height of the dot.
Sample data based on a wheel with a 26-inch diameter.
The data are recorded to the nearest eighth-inch.
Distance wheel moves |
0 |
12 |
24 |
36 |
48 |
60 |
72 |
84 |
96 |
Height above the floor of dot |
0 |
5.25 |
16.5 |
25.125 |
24.125 |
14.25 |
3.375 |
0.25 |
7.125 |
Distance wheel moves |
108 |
120 |
132 |
144 |
156 |
168 |
180 |
192 |
204 |
Height above the floor of dot |
18.75 |
25.75 |
22.75 |
11.875 |
2.0 |
0.75 |
9.25 |
20.75 |
26.0 |
Distance wheel moves |
216 |
228 |
240 |
252 |
|||||
Height above the floor of dot |
21.0 |
9.75 |
1.0 |
1.75 |
Be sure to save your data for use in Activity 4.
See part (b) for the pattern that these points will follow.
Sample answer:

Save your graph for use in Activity 4.
In general, student data should be periodic with period 2p r (where r is the radius of the wheel or object used) and amplitude of 2r.
Sample answer based on sample data for Item 4:
These data were based on a 26-inch wheel diameter. The period is 26p in. (the circumference of the wheel) » 81.7 in. and the amplitude is 13 in., half of the wheels diameter.
Sample answer:

To get height values corresponding to wheel movement in the negative direction, reposition the wheel at zero and roll it in the opposite direction.
Use your the extended version of your graph from part (a) to answer the remaining items.
Sample answer: approximately 40, 40, 120, 205. You get these answers from your graph by determining the x-values that correspond to the peaks in the graph.
Sample answer: approximately 62, 11, 20, 62, 102, 143, 183, 225. The dot is horizontal to the axle when it is 13 in. high (half of the wheels diameter). Draw the line y = 13 and then find the x-values that correspond the points of intersection between the graph and line.
Homework 3Going Around in Circles |
If the radius of the wheel is increased, then both the period and amplitude of the height-versus-distance graph would increase. If the radius of the wheel were decreased, then both the period and amplitude of the wheel would decrease.
For parts (b) (e), imagine reworking Activity 3 using a wheel that has a one-foot radius.
2p ft » 6.28 ft
p » 3.14 ft; 3p » 9.42 ft
The shape of the curve should be similar to the one drawn for Item 3(b) but should oscillate between heights of 0 ft and 2 ft.

The period is 2p » 6.28 ft and the amplitude is 1 ft.
Calculations related to circles of radius 1 (such as in Item 1) are usually simpler than calculations related to circles with different radii. In an effort to keep things simple, mathematicians often base their study of periodic behavior on a unit circle, a circle with a one-unit radius that is centered at (0,0). We will use a unit circle with a radius of 1 foot for this discussion.
Imagine an ant walking along the edge of a unit circle. Suppose that as the ant walks, it pushes a straight blade of grass anchored at the circles center. The ant starts at the point (1,0). The ant can choose to walk either in the positive directioncounterclockwise (as shown in Figure 12) or in the negative directionclockwise. Suppose after walking for a while the ant stops. The initial position of the blade of grass (on the horizontal axis) and its new position forms an angle q, called a central angle. Note also, that as the ant moves, the blade of grass sweeps through a portion of the circles circumference forming an arc. (See shaded portion of circles circumference in Figure 12.)
One convenient way to measure this angle is by the ratio of the arc length, with " + or " to show direction, to the radius of the circle.
q = (± arc length)/radius
The size of the angle that describes to location of our ant is:
q = (+ 1.13 ft)/1 ft = 1.13
The unit circle makes the numerical part of the calculation easy, because we are dividing by 1. However we must always carry out the division to make the unit of measure behave properly. The size of the angle is expressed by a number that has no units. The size of an angle described this way is expressed in radian measure, but it has no units. The size of the angle, q, in the drawing is 1.13. Mathematicians have agreed to call an arc length measured in the counter clockwise direction "+", and one measured in the clockwise direction "".

Figure 12. Ant walking an arc on a unit circle
The ant is back at (1,0). It has walked once around the circle.
It has walked twice around the circle in a clockwise direction.
It has walked half-way around the unit circle in the counterclockwise direction. It is at the point (1,0).

Figure 13. Two arcs representing two walks
Answer:
For Walk #1, the ant traveled about 3/8th of the way around the circle. A trip once around the circle is 2p. So, the ant walked (3/8)( 2p) = 3p /4. This answer is positive because the ant was walking in the counterclockwise direction.
The ant walked 1/2 the circle. The radian measure of the angle that describes the walk is:
q = p ft/1 ft = p

Figure 14. Graph of unit circle.
Radian measure of central angle |
p |
3p/4 |
p/2 |
p/4 |
0 |
p/4 |
p/2 |
3p/4 |
Height (vertical displacement from horizontal axis) in ft |
||||||||
Radian measure of |
p |
5p/4 |
3p/2 |
7p/4 |
2p |
9p/4 |
5p/2 |
11p/4 |
Height (vertical displacement from horizontal axis) in ft |
Table 2. Height-versus-angle data from a unit circle
Student answers should be similar to those in the table below.
Radian measure of central angle) |
p |
3p/4 |
p/2 |
p/4 |
0 |
p/4 |
p/2 |
3p/4 |
Height (vertical displacement from horizontal axis) in ft |
0.0 ft |
0.7 ft |
1.0 ft |
0.7 ft |
0 ft |
0.7 ft |
1.0 ft |
0.7 ft |
Radian measure of central angle |
p |
5p/4 |
3p/2 |
7p/4 |
2p |
9p/4 |
5p/2 |
11p/4 |
Height (vertical displacement from horizontal axis) in ft |
0 |
0.7 |
1.0 |
0.7 |
0 |
0.7 |
1.0 |
0.7 |

Figure 15. Axes with scaling used for Item 3(b).

The graph in Item 1(b) has y = 1 for its axis of oscillation. The graph in part 3(b) has y = 0 as its axis of oscillation. Both graphs have the same period and amplitude.
As the ant (or rotating dot or Ferris wheel rider) moves from its starting position, the point (1, 0) on the unit circle, a graph of its height versus its central angle (use radian measure) results in the oscillating graph that you drew in Item 3(c). The new function that produces this graph is called the sine function.
Calculators screen:

The reason that you are able to determine the central angle on a unit circle is because you know that the radius of the unit circle is one unit, whatever that unit happens to be. So if the ants walk corresponds to a central angle of 3, that means that the ant has traveled an arc equivalent to three radii (each of one unit) placed end-to-end. Using radian measure to describe the size of angles, allows you to generalize the concept to larger circles. As you can see from Figure 16, a central angle of 3 on a unit circle, corresponds to an arc length that measures (3´radius). This arc extends nearly halfway around the circle, regardless of the circles size. Similarly, a central angle of 3p/4 » 2.4 corresponds to an arc that goes 3/8 of the way around the circle in the opposite direction, regardless of the circles size.

Figure 16. Central angles measuring 3 and 3p/4 or
2.36 on circles of different radii.
The dot has traveled (2p)(10 ft) = 20p ft. The central angle corresponding to this turn is 2p.
The distance the dot has traveled, the arc length, is 10p ft q = 10p ft /10 ft = p. The dot has turned half of the way around the circle and is located at (10,0).
q = s ft/10 ft = s/10.
The dot has traveled in the clockwise direction. The formula
p/4 = 5/10 ft
s = (p/4)(10 ft) = (5p/2) ft.
The dot travels a distance of 5p/2 ft. The dot is located midway on the arc connecting (0,10) and (10,0).
The dot has traveled (2p )(20 ft.) = 40p ft. The central angle corresponding to this turn is 2p.
Use the relationship p/4 = s /20. The dot has traveled 5p ft in the clockwise direction.
The dot is located midway on the arc connecting (0,20) and (20,0). It makes the same angle with the positive horizontal axis as does the dot from Item 4(d).
Use the relationship p/4 = s /r. The dot has traveled (p/4)r ft in the clockwise direction.
Sample answer. Place the wheel so that its axle is directly over the 0 marker on the tape measure. Then place a dot level horizontally with the wheel but opposite to the direction in which you will roll the wheel. Make all measurements, both height and distance-rolled in radius units. For example, if the wheel has a 26-inch diameter, then 13 inches constitutes a unit.
Activity 4Learning A, B, C, and D |
= 11, 12
Your graph in Item 3b, Activity 3, based on your wheel data, had the same shape as the sine curve. So, did the graph of the moon data (Item 1(d),Activity 1) and your graph of a Ferris-wheel riders height over time (Item 4(b),Activity 2). The periods, amplitudes and axes of oscillation, however, were different from the graph of y = sin(x).
Perhaps a sinusoidal function, a function that can be expressed by an equation of the form y = A sin(Bx + C) + D, could be used todescribe each of these situations. First, youll need to find out what each of the control numbers A, B, C, and D control before you can fit equations of this form to data.
Begin with the equation y = sin(x) (here, A = 1, B = 1, C = 0, and D = 0). Then change the value of one control number at a time to determine how changing this number affects the graph. Write a summary of the results of your investigation. Include in your summary sketches of graphs that show how changing the values of A, B, C, or D affects the sine graph.
(Warning: Make sure that your calculator is in Radian mode for this investigation.)
Sample answer:
Changing the value of A changes the amplitude of the sine wave. The effect of multiplying by A where A > 1 is to stretch the wave vertically. The effect of multiplying by A where 0 < A < 1 is to compress the wave vertically. If the sign of A is negative, then the wave reflects over the x-axis. Upward loops of the wave turn into downward loops and vice versa. Here are some graphs that support these conclusions.

The value of B affects the period of the wave. If B > 1, the period gets smaller; if 0 < B < 1, the period gets longer. The period and B are related by period = 2p/B or B = 2p/period. Below are some sample graphs.

When you change the value of C, neither the period nor amplitude are changed. If C is positive, the graph moves C units to the right; otherwise the graph shifts left.

Adding D to the sine function shifts the graph up D units if D is positive and down if D is negative.

C
D
A; the amplitude = A
Period = 2p/B
y = sin(0.5x)
y = sin((2/3)x)
y = sin(px)
y = sin(0.2p x)
The sine wave is stretched vertically to three times its original height and then shifted up two units. The period is still 2p. The amplitude changes from 1 to 3.

The graph shifts to the right p/2 units and gets compressed to half its original height. The period does not change. The amplitude is 1/2.

The graph shifts to the left p/2 units and is compressed horizontally by a factor of 2.

Sample answer:
The wheel used in Activity 3 had a 26-inch diameter. That means that A = 13 and D = 13. You get the period from the wheels circumference which is 2p(13) = 26p. So, B = 2p/26p = 1/13 » 0.077. So far, the model is y = 13 sin(0.077 x) + 13.
However, for the wheel data, the first data point was collected when the dot was at the bottom of the wheel, and x = 0. The angle is 3p/2 so [B(0) + C] = 3p/2, then C + 3p/2. The problem starts with x = 0 and the angle between the horizontal and a radii through the dot is (3p/2). The phase constant, C, is: 3p/2. Our final model is y = 13 sin(0.077x 3p/2) + 13.
Sample answer:
Below is a scatter plot of the sample data from Item 2, Activity 3. The model from part (a) has been superimposed on the scatter plot. The model appears to fit these data very well.

Homework 4Sine Up! |

The amplitude of y = 3 sin(2x) is 3 and the period is p. The amplitude of y = sin(x) is 1 and the period is 2p.

They have the same amplitude but the period of the first graph is one-fourth the period of the second.
y = A sin(Bx + C) + D,
the value of C controls the horizontal shift of the graph and is called the phase shift. One way to think of C is that C is the angle when we start at x = 0,
y = A sin(Bx + C) + D.
y = 0.75 sin(0.5x p/4)

y = sin(2/3x + p/3)

y = 2 sin(x p) + 1


Figure 17. Graph of a sinusoidal function
y = 2 sin(x) + 2.

Figure 18. Graph of a sinusoidal function
y = sin(2x) 1

Figure 19. Graph of a sinusoidal function.
y = 2.5 sin(0.5x 0.5)

Figure 20. The height of the hooves of a
carousel horse versus time.
The period is 10 seconds and the amplitude is 1.
A = 1; B = 2p/10 » 0.63; C = 2.5.
Model: y = sin(0.63x 1.57) + 15.
Sample answer: Assumption: The wheel moves at a constant speed turning 2.6 revolutions per minute. (Thus, the fact that the wheel takes several seconds to get up to its constant speed is ignored.) Time starts when she leaves the ground the first time, in seconds.
Amplitude: A = 29.50/2 = 14.75 meters.
Period: The wheel makes 2.6 revolutions per minute, hence it takes approximately 23.08 seconds to make one complete turn. To get a period of 23.08 seconds, B = 2p/23.08 » 0.27.
Axis of oscillation: The wheel is 33.00 meters high with a diameter of 29.50 meters. This means that the bottom of the wheel is 3.50 meters above the ground. Therefore D = 3.5 + (29.50)/2 = 18.25
Phase shift: At t = 0, Anne is at the bottom of the circle. The value of the angle, measured counterclockwise from the horizontal is
3p/2
C = 1.57
The model is:
y = 14.75sin(0.27t + 2p/3) + 18.25.
Activity 5Moonlight and Sunlight |
Now its time to apply what you have learned about graphs of sinusoidal equations to situations that you first studied in Activity 1.
Date |
1/5 |
1/10 |
1/15 |
1/20 |
1/25 |
1/30 |
2/4 |
Day of year |
5 |
10 |
15 |
20 |
25 |
30 |
35 |
Portion illuminated |
0.20 |
0.02 |
0.43 |
0.89 |
0.98 |
0.66 |
0.17 |
Date |
2/9 |
2/14 |
2/19 |
2/24 |
3/1 |
3/6 |
3/11 |
Day of year |
40 |
45 |
50 |
55 |
60 |
65 |
70 |
Portion illuminated |
0.04 |
0.48 |
0.91 |
0.97 |
0.63 |
0.12 |
0.07 |
Date |
3/16 |
3/21 |
3/26 |
3/31 |
Day of year |
75 |
80 |
85 |
90 |
Portion illuminated |
0.52 |
0.92 |
0.96 |
0.57 |
Figure 21. Illuminated portion of the moon.
Sample answer:
On day 10, 0.2 of the moons surface is illuminated and on day 40, 0.04 of the moons surface is illuminated. So, the period is slightly less than 30 days; say, 29 days. The amplitude is 0.5, half way between 0 and 1.
No, y = sin(x) does a very poor job in modeling the pattern of the moon data. Here is a graph that displays what students might see in their calculators screen.

The graph of y = 0.5 sin(2p/29x) or approximately y = 0.5 sin(0.22x) does not do a good job in describing these data. The graph needs to be shifted both vertically and horizontally to fit these data.
Sample answer:
Students models will vary. Here is an example of what you might expect for an answer.
The moon data oscillate between 0 and 1. The graph of the equation in (c) oscillates between 0.5 and 0.5. So, first add 0.5 to the equation to shift the graph vertically. Next, the graph must be shifted horizontally. The function y = 0.5 sin(0.22 x) + 0.5 attains its maximum value for the first time at approximately 7.35. The data reach 0.98 (very close to the maximum value) for the first time on day 25. That means that the function needs to be changed so that the graph shifts approximately 17.65 days. Then C/B = 17.65/0.22 and C » 80. After we looked at the graph of y = 0.5 sin(0.22x 80) + 0.5, it appeared that it was shifted slightly too far to the right. Through experimentation we decided that the model y = 0.5 sin(0.22x 79) + 0.5 did a reasonably good job in describing these data. The data fell very close to the graph of this function.
Sample answer: We probably should have adjusted our equation even further because more of the residuals were positive than negative; however, the average of residuals was 0.04 which is fairly close to zero. So, we decided to leave our equation from (d) alone.
You may find the 1997 Calendar on Handout 2 helpful in answering Item 2.
Sample answer based on the model y = 0.5 sin(0.22x 79) + 9:
The day numbers for days in April 1997 are from 91 to 120. Graph the model above using the interval from 91 to 120 for Xmin and Xmax. Use 2nd CALC Maximum to determine the coordinates for the curves maximum in this interval. This gives day number 110. Day number 110 corresponds to April 20 which turns out to be a Sunday.
The day numbers for September 1997 are from 244 to 273. Graph the model y = 0.5 sin(.22x 3.78) + 0.5 using the settings Xmin = 244 and Xmax=273. The moon reaches its maximum on about day number 253. This day corresponds to September 10th which is a Wednesday. So they should rent the cabin either for September 67 or September 1314. The portion of the moon that is illuminated on September 7th is approximately 0.90; the portion of the moon that is illuminated on September 13 is 0.89. So, the September 67 weekend might be slightly better than the September 1314 weekend, however, the difference probably would not be noticeable.
Sample answer: The day numbers for November 1997 are from 305 to 334. Graph the model y = 0.5 sin(0.22x 3.78) + 0.5 using the settings Xmin = 305 and Xmax=334. The graph reaches its minimum on days 319 or 320. So the mission should take place on November 15 or 16.
Date |
12/31 |
1/30 |
3/1 |
3/31 |
4/30 |
5/30 |
6/29 |
7/29 |
Day Number |
0 |
30 |
60 |
90 |
120 |
150 |
180 |
210 |
Length (hours) |
9.1 |
9.9 |
11.2 |
12.7 |
14.0 |
15.0 |
15.3 |
14.6 |
Date |
8/28 |
9/27 |
10/27 |
11/26 |
12/26 |
1/25 |
2/24 |
3/26 |
Day Number |
240 |
270 |
300 |
330 |
360 |
390 |
420 |
450 |
Length (hours) |
13.3 |
11.9 |
10.6 |
9.5 |
9.1 |
9.7 |
11.0 |
12.4 |
Figure 22. Data on length of day.
Sample answer:
The period should be 365 days (except for leap years): So B = 2p /365 » 0.017.
A » 0.5(15.3 9.1) = 3.1.
D = 0.5(15.3 + 9.1) = 12.2.
C = the horizontal shift required to translate y = 3.1 sin(0.017 t) + 12.2 to match these data as closely as possible. The graph of this model reaches a maximum at t = 92.4 whereas the data reaches its maximum at around 180 days. So, try using C = 1.53. After looking at a graph of the function using this phase shift, it appeared that the shift was slightly too large. After some experimentation, it appeared that using C = 1.40 produced a model that better fit the pattern of these data.
Model: y = 3.1 sin(0.17t 1.40)
Using the SinReg on the TI-83 yields approximately:
y = 3.02 sin(0.017t 1.40) + 12.21.
The constants chosen for A, B, C, and D by the calculator were fairly close to the ones determined for the model in (a).
March 21, 1999 corresponds to day 445. According to the model in (b), there are approximately 12.15 hours of daylight on March 21, 1999.
December 21, 1998 corresponds to day number 355. According to the model in (b), there are approximately 9.49 hours of daylight. She should sit in front of the light for 2.66 hours.
The model to determine the number of hours of light therapy, T, is:
T = 12.15 3.02 sin(0.017T 0.023) 12.21. The graph of this function over the interval from T = 355 to T = 445 appears below.

January 15, 1999 is day 380. According to the model in (e), she should sit in front of the light for approximately 2.77 hours, or about 2 hours 46 minutes.
AssessmentModeling Ferris Wheel Rides |
Recall the details of the popular 33-meter, 44-meter, and 55-meter Ferris wheels.
Wheel height (meters from ground to |
Wheel diameter |
Revolutions per Minute |
33.00 |
29.50 |
2.6 |
44.00 |
40.70 |
1.5 |
55.00 |
52.00 |
1.5 |
Figure 23. Technical details for three popular Ferris wheels.
Sample answer:
Assumption: The wheel moves at a constant speed turning 2.6 revolutions per minute. (Thus, the fact that the wheel takes several seconds to get up to its constant speed is ignored.) Time starts when she leaves the ground the first time, in seconds.
Amplitude: A = 29.50/2 = 14.75 meters.
Period: The wheel makes 2.6 revolutions per minute, hence it takes approximately 23.08 seconds to make one complete turn. To get a period of 23.08 seconds, B = 2p/23.08 » 0.27.
Vertical shift: The wheel is 33.00 meters high with a diameter of 29.50 meters. This means that the bottom of the wheel is 3.50 meters above the ground. Therefore D = 3.5 + (29.50)/2 = 18.25
Phase shift or horizontal shift: Assume that when t = 0 Anne is at the bottom of the wheel and that the wheel makes one complete turn every 23.08 seconds. Under these assumptions, Anne reaches the midpoint between the bottom of the wheel and top of the wheel when t » 23.08/4 » 5.77 seconds. So, the phase shift is 5.77 seconds. Then C = (5.77/23.0)(2p) = 1.57.
The model is y = 14.75sin(0.27x 1.57)) + 18.25.

Between 9.2 and 14.0 seconds; between 32.5 and 37.3 seconds; and between 55.7 and 60.5 seconds. The answer was determined by graphing y = 30 and using the intersect feature on the TI-83 to determine the points of intersection of the line and sinusoidal function.
If the rate of change in height over time were constant, the graph would be a line. However, the graph is a smooth oscillating curve. Therefore, the rate of change of height with respect to time is not constant.

The times that correspond to the vertical line indicate the times when Annes height above the ground is changing most rapidly: at approximately 6, 17, 29, 40, 52, and 64 seconds into the ride. This is where the absolute value of the "slope" of the graph is greatest.
At each of these times her seat is midway between the bottom and the top of the wheel as shown on the wheel below.

Amplitude is 20.35; period is 40 seconds per revolution and B = 2p/40 » 0.157; vertical shift is 3.30 + 20.35 = 23.65 meters; horizontal shift is 40/4 = 10 seconds, C = (10/40)(2p) = 1.57.
y = 20.35 sin(0.157x 1.57) + 23.65
Amplitude is 26.00; period is 40 seconds and so B is the same as in Item 2; vertical shift is 3.00 + 26.00 = 29.00; the horizontal shift is the same as in Item 2. Model: y = 26.00 sin(.157x 1.57) + 29.
The graph with the larger amplitude corresponds to the 55-meter wheel; the smaller amplitude to the 44-meter wheel.

Two features enhance the thrill of a ride: (1) how high the riders can go and (2) how fast the riders heights change. The 55-meter ride carries riders higher above the ground than the 44-meter ride. In addition, when riders are midway between the top and bottom of the wheel (thats when their height is changing most rapidly), their height is changing more rapidly on the 55-meter ride than on the 44-meter ride. The times for reaching the highest point on the ride and the times when height changes most rapidly coincide for the two rides. The vertical lines on the graph above indicate the times when the riders heights are changing most rapidly.
Unit ProjectSwing Dance |
So far the only activities that generated periodic data have involved rolling round objects. In this activity you will use a motion detector setup to collect periodic data that do not come from rolling objects.
You will need the apparatus for the motion detector set-up, string, and a plastic water or soda bottle or some other object that can be used for a plumb. You will also need a stopwatch or clock with a second hand and a meter (or yard) stick.

Figure 24. Pendulum set-up.
Sample answer: 48 inches.
Sample answer: 14 inches.
Sample answer: 4 times.
Sample answer:
Yes there is enough information to write an equation.
Amplitude is 14 in. so, A = 14.
There were 4 swings in 10 seconds so the period is 2.5 seconds. B = 2p/2.5 » 2.51.
The axis of oscillation is 48, so D = 48.
The bottle reaches the level of its axes of oscillation when it is 1/4 of the way through a cycle, when t = 2.5/4 =0.625, so C = (0.625/2.5)(2p) = 1.57.
The equation is d = 14 sin(2.51t 1.57) + 48 or y = 14 sin(2.51x 1.57) + 48.
Sample results appear below. The program Slinky was used instead of Pendulum which explains why the vertical axis is labeled as height and not distance. (Slinky and Pendulum are similar programs and can be used interchangeably.)

Sample answer: The equation from 2(d) did not fit well at all. The motion detector recorded readings in feet and we had measured distances in inches. After converting the constants A and D to feet, we re-expressed our model as
d = 1.67 sin(2.51t 1.57) + 4 or y = 1.67 sin(2.51x 1.57) + 4
That produced a graph that was out of phase with our data and had too large an amplitude. (We should have been more careful to pull the soda bottle back the same distance in both experiments.) There were four times in our data when the soda bottle appeared to be farthest from the motion detector. We averaged these readings to get an estimate of the farthest distance the soda bottle was from the motion detector (5.35 feet). We then did the same to arrive at a minimum distance (3.40 feet). That gave us this estimate for amplitude: A = 0.5(5.35 3.40) » 0.98.
This changed our axis of oscillation to 0.5(5.35 + 3.40) » 4.38. (So, we know we didnt measure the distance from the motion detector to the free hanging bottle very carefully in the first experiment.
We averaged the four times to get from maximum to maximum to get an approximate period of 2.5. That was exactly what we got in our first experiment.
Finally, our graph was out of phase with the data. The first "peak" in the graph of a sinusoidal function with period 2.5 and phase shift 0 occurs at t = 0.625 sec. The first "peak" in our data occurred at approximately t = 2.20 sec. So, C = 2.20 0.625 = 1.575.
Our model: y = 0.98 sin(2.51t 3.95)) + 4.38
This model fits these data beautifully!
Sample answer: If you pull the bottle farther back before letting it swing, that should increase the amplitude of the data collected. We pulling the bottle back farther and discovered that the amplitude for our new data was 1.2 ft instead of 0.98 feet from Experiment #2.
Then we ran an experiment where we didnt pull the bottle back as far. The amplitude for our data from this experiment was 0.65 ft.
If students shorten or lengthen the string that will change the period. Some students may suggest changing the weight in the bottle. If so, then that should be tested also.
If the TRIGGER button is pressed exactly when the bottle reaches the bottom of its swing (when the string is vertical) then the phase shift should be 0. Even though we were able to get a smaller value for the phase shift, we never were able to time this perfectly and get a phase shift of 0. However, we did learn that we could affect the value of the phase shift by pressing the TRIGGER button at different points during the pendulums swing.
Mathematical Summary |
This unit deals with functions whose graphs are periodic; their graphic patterns repeat over fixed intervals. The period of a periodic function is the shortest horizontal length of the basic repeating shape of its graph. The amplitude is half the vertical height (top and bottom) of the basic repeating shape. The sine function is an example of a periodic function.
The sine function is defined as the vertical displacement (height) versus the radian measure of an arc made by a dot rotating around a unit circle. Any function of the form
y = Asin(Bt + C) + D
belongs to the family of sinusoidal functions. The control numbers A, B, C, and D control the graphs amplitude, period, phase shift, and axis of oscillation, respectively.
When fitting a sinusoidal model to data by hand, you need to use the information contained in your data to estimate the values of the control numbers A, B, C, and D. Here is one method of estimating values for the control numbers. Sometimes, however, a variant of this method will provide better results. So, dont get locked into a single method.
Many calculators have sinusoidal regression as one of their regression capabilities. If you have such a calculator, you can use sinusoidal regression to fit sinusoidal models to data. However, you may need to adjust the model fit by your calculator if the period or amplitude of the data are predetermined by the context.
Key Concepts |
Amplitude (of a periodic function): Half of the fixed vertical height of the basic repeating shape; that is, half of the difference between the maximum and minimum values of the periodic graph.
Axis of Oscillation (of an oscillating function): The center of oscillations, determined as the horizontal line midway beween the maximum and minimum values of the graph.
Frequency: The number of oscillations per second. The value of the frequency for a periodic function is 1/period.
Oscillating motion: Motion that alternates back and forth between two extremes about some mean value (the axis of oscillation).
Period (of a periodic function): The shortest horizontal length of the basic repeating shape.
Periodic function: Function that repeats itself on intervals of a fixed length (equal to the period).
Phase shift: A horizontal shift of a periodic function from a standard reference function. In particular, the phase shift for functions of the form y = A sin(Bx + C) + D is C. This is the angular shift required to translate the graph of y = Asin(Bx) + D so that it coincides with the graph of y = A sin(Bx + C) + D. The quantity, C, is the size of the phase shift.
Radian measure of an angle: The ratio of a directed length of an arc that begins at (1, 0) on the unit circle, to the length of the radius, when both are measured in the same units. If the arc turns is in the counterclockwise direction, the radian measure is positive; if it turns in the clockwise direction, the radian measure is negative.
Sine function: The vertical displacement, from the horizontal axis, of a point on the unit circle. The input for the sine function is the radian measure of the central angle.
Sinusoidal function: Any function that can be expressed in the form y = A sin(Bx + C) + D, where neither A nor B are zero.
Unit circle: Circle with radius one unit centered at the origin.
Solution to Short Modeling Practice |
Use technology to graph the data of the motion in the x direction. Using only what you observe from the graph, estimate the values of A, B, C, and D in the general form of the sine function.
y = Asin(Bt + C) + D

Sample answers:
The estimates should be close to these values:
For X A ~ 5.0
Period ~ 1.3 seconds, then
B » 2p/1.3 » 4.7
x = 5.0cmsin(4.7t) from graphical estimates.
Use the sin regression tools of the calculator to check your estimates of the values for A, B, C, and D.
The regression should give A = 4.909, B = 4.71, C=0.001, and D = 0.0003. C and D are small enough to be rounded to zero.
Write an equation that models the motion in the x direction.
The model is: x = 5.0 sin(4.71t)
Use technology to graph the data of the motion in the y direction. Using only what you observe from the graph, estimate the values of A, B, C, and D in the general form of the sine function.

For Y, A ~ 4.0cm, Period ~ 1.3 seconds, B » 2p/1.3 » 4.7
Use the sin regression tools of the calculator to check your estimates of the values for A, B, C, and D.
The regression should give A = 4.00, B = 4.71, C = 1.57, and C = 0.0001.
Write an equation that models the motion in the y direction.
The model is: y = 4.0 sin(4.71t + 1.57)
Use the sine functions that you have produced in Part 1 and Part 2. Graph the x and y positions at the same time using your calculator.
The graph of both x and y should be similar to:

Look at the curve for the y position. Find where it first crosses the horizontal axis. Notice the alignment of this "zero crossing" with the first peak on the x curve. Then the sine function is at this first peak value, the argument of the sine function (the value of the complete expression within the parenthesis sin(argument)) is always (p/2). The phase difference between the x position and the y position is p/2.
A sine function that is phase shifted p/2 ~ 1.57, is called a cosine function. The cosine function is the same as the sine function, except for the phase shift. The x and y positions can be modeled using either two sine function, or one sine function and one cosine function.
x position: a = Axsin(Bt)
y position: y = Aysin(Bt + (p/2)) or y = Aycos(Bt)>
Use the pairs of x and y data that have matching times to form ordered pairs (x, y).
Graph these ordered pairs of (x, y) data on a sheet of graph paper to determine the path the moving tray is following.

Solutions to Practice and Review Problems |
EXERCISE 1
EXERCISE 2
EXERCISE 3
EXERCISE 4
About 131.95 feet
EXERCISE 5
About 201.06 m2
EXERCISE 6
Revolutions = Total inches ¸
Inches per revolution
Revolutions = 6.336 ´ 108 inches ¸ 72.2 inches per revolution
Revolutions = 8,800,000 revolutions
EXERCISE 7
The students sketch of the pool and sidewalk should appear generally as shown below.

The radius of the pool is 1/2 the diameter, or 16 feet. The radius of the outer edge of the sidewalk is an additional 5 feet, or 21 feet in all.
EXERCISE 8
EXERCISE 9
Speed = Wavelength ´ Frequency
So, solving for the wavelength and substituting...
Wavelength = Speed/Frequency
Wavelength = 73.3 fps/1.2 cps
Wavelength = 61 feet per cycle (rounded)
The road breaks, corresponding to the bouncing of the car, are approximately 61 feet apart.
EXERCISE 10
The amplitude of wave 1 is 5 V/div´ 2 div = 10 V.
The amplitude of wave 2 is 5 V/div ´ 1 div = 5 V.
The period of wave 1 is 50 msec/div ´ 2 div/cycle = 100 msec per cycle.
The period of wave 2 is 50 msec/div ´ 2 div/cycle = 100 msec per cycle.
The frequency of wave 1 is 1/0.100 sec per cycle = 10 Hz.
The frequency of wave 2 is 1/0.100 sec per cycle = 10 Hz.
EXERCISE 11
Time (sec) |
Voltage (V) |
Time (sec) |
Voltage (V) |
0 |
0 |
0.10 |
0 |
0.01 |
82.29 |
0.11 |
82.29 |
0.02 |
133.15 |
0.12 |
133.15 |
0.03 |
133.15 |
0.13 |
133.15 |
0.04 |
82.29 |
0.14 |
82.29 |
0.05 |
0 |
0.15 |
0 |
0.06 |
- 82.29 |
0.16 |
- 82.29 |
0.07 |
- 133.15 |
0.18 |
- 133.15 |
0.08 |
- 133.15 |
0.18 |
- 82.29 |
0.09 |
- 82.29 |
0.19 | 0
- 82.29 |
0.20 |
0 |

EXERCISE 12
T = 2p ´ 

Yes, the period is closer to the desired value. (If the students use a rounded value for p, slightly different answers might occur.
EXERCISE 13

EXERCISE 14
EXERCISE 15